Answer:
A+B do (1/12)th in a day.
B and C do (1/15)th in a day
A and C do (1/20)th in a day
2A+2B+2C = (1/12)+(1/15)+(1/20) = [300+240+180]/(12*15*20) =720/3600 = 1/5, or
A+B+C do 1/10th in a day.
A alone does (1/10)-(1/15) = (15–10)/(10*15) = 5/150 = 1/30th in a day.
So. A alone does the same work in 30 days.
Step-by-step explanation:
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Verified answer
Answer:
A+B do (1/12)th in a day.
B and C do (1/15)th in a day
A and C do (1/20)th in a day
2A+2B+2C = (1/12)+(1/15)+(1/20) = [300+240+180]/(12*15*20) =720/3600 = 1/5, or
A+B+C do 1/10th in a day.
A alone does (1/10)-(1/15) = (15–10)/(10*15) = 5/150 = 1/30th in a day.
So. A alone does the same work in 30 days.
Step-by-step explanation: