(a) An electric iron has markings 220 V 50Hz and 1 kW on it. Explain the significance of these markings. Can this electric iron be used both on AC and DC? Give reason.
(b) Calculate the resistance of the heating element of this electric iron.
plz give me correctly answer 22
(b) Calculate the resistance of the heating element of this electric iron.
plz give me correctly answer 22
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Answer:
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(a) Explanation of markings on the electric iron:
1. 220 V: This marking indicates the voltage rating of the electric iron. It means the iron is designed to operate at a voltage of 220 volts. When connected to a power supply with this voltage, the iron will function properly and provide the expected heating effect.
2. 50Hz: This marking represents the frequency of the alternating current (AC) that the electric iron is designed to operate on. In this case, the iron is designed to work with an AC power supply that has a frequency of 50 Hertz (cycles per second). Most household power supplies around the world operate at a frequency of 50 Hz or 60 Hz.
3. 1 kW: This marking indicates the power rating of the electric iron, which is 1 kilowatt (1000 watts). Power is the rate at which energy is consumed or transformed. The higher the power rating, the faster the iron can heat up and perform its function.
Can this electric iron be used on both AC and DC? Reason:
No, this electric iron is designed to work only on AC (Alternating Current) and not on DC (Direct Current). The reason is that the heating element of the iron is specifically designed to work with the characteristics of AC power. The heating element's resistance and other electrical properties are optimized for the voltage and frequency of AC.
Using this electric iron on DC would not be efficient, and the heating element might not function properly. Moreover, connecting the iron to a DC power source could cause damage to the heating element and other components, as it is not designed to handle the constant and unidirectional flow of current that DC provides.
(b) Calculation of resistance of the heating element:
We know the power rating of the electric iron is 1 kW, which is equivalent to 1000 watts.
Power (P) = 1000 watts
Voltage (V) = 220 V
The relationship between power, voltage, and resistance is given by the formula:
Power (P) = Voltage (V)^2 / Resistance (R)
We can rearrange the formula to solve for resistance (R):
Resistance (R) = Voltage (V)^2 / Power (P)
Substitute the given values:
Resistance (R) = 220^2 / 1000
Resistance (R) = 48400 / 1000
Resistance (R) = 48.4 ohms
The resistance of the heating element in this electric iron is approximately 48.4 ohms.