A alone can do a piece of work in 12 days and B along can do the same work in 15 days. They start working together. After 4 days B leaves the work. In how many days A alone complete the remaining work?
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Answer:
No. of days, A takes to complete one work= 12
No of days B takes to complete one work= 15
Total work done by both A &B in 1 day= 1/12 + 1/15
= 9/60= 3/20
So, total work done by them in 4 days= 3/20 * 4 = 3/5
The remaining work= 1- 3/5= 2/5
Time taken by A to complete the remaining work= 2/5 / 1/12
2/5*12= 24/5
= 4.8 days
explanation:
So A will complete the remaining work in 4.8 days
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