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Answer:

To calculate the force of gravitational attraction between the boy and the girl, we'll use Newton's law of universal gravitation:

\[ F = G \times \dfrac{{m_1 \times m_2}}{{r^2}} \]

where:

- \( F \) is the gravitational force between the boy and the girl,

- \( G \) is the gravitational constant (\(6.67430 \times 10^{-11} \, \text{m}^3 \text{kg}^{-1} \text{s}^{-2}\)),

- \( m_1 \) is the mass of the boy (\(65 \, \text{kg}\)),

- \( m_2 \) is the mass of the girl (\(50 \, \text{kg}\)),

- \( r \) is the distance between them (\(1.5 \, \text{m}\)).

i) **Calculate the force of attraction (gravitational)**:

\[ F = G \times \dfrac{{65 \times 50}}{{1.5^2}} \]

ii) **Determine the gravitational field strength of the girl at the boy's position**:

\[ g = \dfrac{{G \times m_2}}{{r^2}} \]

where:

- \( g \) is the gravitational field strength at the boy's position.

Let's proceed with the calculations.

i) **Calculate the force of attraction (gravitational)**:

\[ F = G \times \dfrac{{65 \times 50}}{{1.5^2}} \]

\[ F \approx 1.287 \times 10^{-7} \, \text{N} \]

ii) **Determine the gravitational field strength of the girl at the boy's position**:

\[ g = \dfrac{{G \times 50}}{{1.5^2}} \]

\[ g \approx 1.777 \times 10^{-8} \, \text{N/kg} \]

So, the gravitational force of attraction between the boy and the girl is approximately \(1.287 \times 10^{-7} \, \text{N}\), and the gravitational field strength of the girl at the boy's position is approximately \(1.777 \times 10^{-8} \, \text{N/kg}\).