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SOLUTION:

Step 1: List the given values.

To convert the temperature from degree Celsius to kelvin, add 273 to the temperature expressed in degree Celsius.

[tex]\begin{aligned} & P_1 = \text{733 mmHg} \\ & V_1 = \text{5.36 L} \\ & T_1 = -25^{\circ}\text{C} = \text{248 K} \\ & P_2 = \text{1.5 atm = 1140 mmHg} \\ & T_2 = 128^{\circ}\text{C} = \text{401 K} \end{aligned}[/tex]

Step 2: Calculate the final volume using combined gas law.

[tex]\begin{aligned} \frac{P_1V_1}{T_1} & = \frac{P_2V_2}{T_2} \\ V_2P_2T_1 & = V_1P_1T_2 \\ \frac{V_2P_2T_1}{P_2T_1} & = \frac{V_1P_1T_2}{P_2T_1} \\ V_2 & = \frac{V_1P_1T_2}{P_2T_1} \\ & = \frac{(\text{5.36 L})(\text{733 mmHg})(\text{401 K})}{(\text{1140 mmHg})(\text{248 K})} \\ & = \boxed{\text{5.57 L}} \end{aligned}[/tex]

Hence, the volume of the gas at 128°C and 1.5 atm is 5.57 L.

[tex]\\[/tex]

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