A 52.0 g-aluminum calorimeter contains 175.0 g of water at 25 degrees Celsius. You continuously stir the water and found that the temperature of the water has risen to 25.3 degrees Celsius. How many joules of work did you do in stirring the water? Neglect the heat absorbed by the stirrer
Answers & Comments
Verified answer
Work done : 219.765 J
Further explanation
Heat can be calculated using the formula:
Q = mc∆T
Q = heat, J
m = mass, g
c = specific heat, joules / g ° C
∆T = temperature difference, ° C / K
Given
mass = 175 g
temperature difference : 25.3 - 25 = 0.3 ° C
Required
Joules of work
Solution
Q absorbed by water(due to the transfer of mechanical energy from stirring)
= 175 g x 1 cal/g ° C x 0.3 ° C
= 52.5 cal
Work(W) = 52.5 cal x 4.186 J/cal = 219.765 J
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