A 4.00 kg ball is on a 5.00 m ledge. If it is pushed off the ledge, how much kinetic energy will it have
just before hitting the ground?
the answer is 196 J
determine how to get to that answer.
just before hitting the ground?
the answer is 196 J
determine how to get to that answer.
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Answer:
m = 4kg, h = s = 5m, g = 10m per sec square
2gh = v^2
v^2 = (2*10*5) = 100 m^ 2 per s^2
1/2mv^2 = 1/2*4*100 J
1/2mv^2 = 200 J
KE=200 J
g=9.8m/s^2
Substitute
(2*9.8*5)=v^2
98=v^2
KE=1/2mv^2
Substitute
KE=1/2(4kg)(98)
KE=196J