A 40-kg ball is pulled to one side until it is 1.5 m above its lowest point. What will be it's velocity as it pases through its lowest point.
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Answer:
the potential energy at the high point is equal to the kinetic energy at the low point
m g h = 1/2 m v^2 ... v = √(2 g h)
the mass is in kilograms , so the height is probably in meters
v = √(2 * 9.8 * 1.5) m/s