Answer:
To solve this question, we need to substitute the values of a and b into the equation. When we do this, the equation becomes:
7² + 2(7)(3) + 3²
We can simplify this equation by multiplying the 2 and 7 and 3 together to get 42, and then substituting a², b² with 49, 9. This gives us:
49 + 42 + 9
Or [tex](a+b)^2[/tex] [Using Identities]
= [tex](7+3)^2[/tex]
= [tex]10^2[/tex]
[tex]\underline{\underline{\bigstar\; \frak{Solution\;:}}} \\\\ [/tex]
[tex]\\\dashrightarrow\quad\sf{{a}^{2}+2ab+{b}^{2}} [/tex]
— Here, it is given that a = 7 & b = 3. So,
[tex]\\\dashrightarrow\quad\sf{{7}^{2} +2\times 7\times 3+{3}^{2}} [/tex]
[tex]\\\dashrightarrow\quad\sf{49+42+9} [/tex]
[tex]\\\dashrightarrow\quad\underline{\frak{100}} [/tex]
Also, it can be written as ;
[tex]\\\longrightarrow\quad\sf{{7+3)}^{2}} [/tex]
[tex]\\\longrightarrow\quad\sf{{(10)}^{2}} [/tex]
[tex]\\\longrightarrow\quad\sf{100} [/tex]
So basically,
[tex]\\\star\; \underline{\boxed{\sf{{a+b)}^{2}={a}^{2}+2ab+{b}^{2}}}} [/tex]
Copyright © 2024 EHUB.TIPS team's - All rights reserved.
Answers & Comments
Verified answer
Answer:
The answer is 100.
To solve this question, we need to substitute the values of a and b into the equation. When we do this, the equation becomes:
7² + 2(7)(3) + 3²
We can simplify this equation by multiplying the 2 and 7 and 3 together to get 42, and then substituting a², b² with 49, 9. This gives us:
49 + 42 + 9
= 100
Or [tex](a+b)^2[/tex] [Using Identities]
= [tex](7+3)^2[/tex]
= [tex]10^2[/tex]
= 100
[tex]\underline{\underline{\bigstar\; \frak{Solution\;:}}} \\\\ [/tex]
[tex]\\\dashrightarrow\quad\sf{{a}^{2}+2ab+{b}^{2}} [/tex]
— Here, it is given that a = 7 & b = 3. So,
[tex]\\\dashrightarrow\quad\sf{{7}^{2} +2\times 7\times 3+{3}^{2}} [/tex]
[tex]\\\dashrightarrow\quad\sf{49+42+9} [/tex]
[tex]\\\dashrightarrow\quad\underline{\frak{100}} [/tex]
Also, it can be written as ;
[tex]\\\longrightarrow\quad\sf{{7+3)}^{2}} [/tex]
[tex]\\\longrightarrow\quad\sf{{(10)}^{2}} [/tex]
[tex]\\\longrightarrow\quad\sf{100} [/tex]
So basically,
[tex]\\\star\; \underline{\boxed{\sf{{a+b)}^{2}={a}^{2}+2ab+{b}^{2}}}} [/tex]