Problem:

A 10.97-meter ladder leans against the top of the parapet wall of the CISSL Candazo Building. The bottom of the ladder makes a 60° with the ground. How high is the school building?

Solution:

One trigonometric ratios form the SOH may be used in order to come up with high of the school building.

Use the given facts to illustrate the problem.

• Let x be the high of the school building.

Solve the mathematical equation.

• sin θ = opposite side/hypotenuse
• sin 60 = x/10.97 m
• x = (10.97 m)(sin 60°)
• x = 9.5003
• x = 9.50

Answer:

• The school building is 9.50 m high.

P.S: Please click on an image seen above to see my right triangle problem.

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Answer:

If A is the angle between ladder &wall then sinA 1.3/10 =.13 use the sin table to get degrees for 0.13 roughly between 7&8 degrees