• Mass of the body (m) = 100 kg.
• The two halves of the rope subtend 120° angle.
• The given condition is in equilibrium.

• The tension in the rope.

Consider the first attachment as the given figure.

Now,

• Let the tension in one half of the string be T.

Let's make the Free body diagram of the given condition .

Refer to attachment 2 for the free body diagram.

As, the given condition is equilibrium so,

So,

The Tension in the string/rope would be 1000 Newtons.

_____________________________

Explanation:

Mass of the body (m) = 100 kg.

The two halves of the rope subtend 120° angle.

The given condition is in equilibrium.

Find:-}}}}

†ToFind:−

The tension in the rope.

Solution:-}}}}

†Solution-

Consider the first attachment as the given figure.

Now,

Let the tension in one half of the string be T.

Let's make the Free body diagram of the given condition .

Refer to attachment 2 for the free body diagram.

As, the given condition is equilibrium so,

\begin{gathered}\colon\implies \sf \; mg = T\:cos\:60\degree+T\:cos\:60\degree\\\\\colon\implies\sf\;100\times\cancel{10}=\cancel2T\:cos\:60\degree\\\\\colon\implies\sf\;100\times5=T\times \dfrac{1}{2}\\\\\colon\implies\sf\;T=500\times2\\\\\co

:⟹mg=Tcos60°+Tcos60°

:⟹100×

10

=

2

Tcos60°

:⟹100×5=T×

2

1

:⟹T=500×2

:→

T=1000N

So,

The Tension in the string/rope would be 1000 Newtons.