CO2
= 12 + 16×2
= 12+ 32 = 44
0.295 / 4 4 =
= 0.0067
= 6.7 × 10-³
456 mm = 0.6 atm
504ml = 0.504 lit
ideal gas constant = 0.082
then
0.6× 0.50= 6.7 × 10-³ × 0.082 × T
0.3/ 6.7× 10-³ × 0.082= T
0.3× 10³ × 10²/ 6.7 × 8.2
0.3× 10⁵/ 54.94
546.05 = T
this temperature is in Kelvin
K= 273.15+ °C
546.05- 273.15= °C
272.90= °C
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Answers & Comments
CO2
= 12 + 16×2
= 12+ 32 = 44
0.295 / 4 4 =
= 0.0067
= 6.7 × 10-³
456 mm = 0.6 atm
504ml = 0.504 lit
ideal gas constant = 0.082
then
0.6× 0.50= 6.7 × 10-³ × 0.082 × T
0.3/ 6.7× 10-³ × 0.082= T
0.3× 10³ × 10²/ 6.7 × 8.2
0.3× 10⁵/ 54.94
546.05 = T
this temperature is in Kelvin
K= 273.15+ °C
546.05- 273.15= °C
272.90= °C