A body is dropped from a certain height and takes 6 seconds to reach the ground .how much time does it take to cover 1/9th the distance starting from top?
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Answer:
2 second
Explanation:
g=10 m/s^2
total height =h
time to cover h=6s
(v-u)/t=g
v=gt=10t
v^2=2gh=20h
100t^2=20h
3600=20h
h=180m
h2=180/9=20m
h2=1/2gt^2
(20*2)/10=t^2
t^2=4
t=2second