Answer:
By using identity ( a - b )² = a² + b² - 2ab
Here a = 1000 and b = 1
[tex](999)(999)\\= (999)^{2} \\= ( 1000 - 1 ) ^{2} \\= (1000)^{2} + (1)^{2} - 2(1000)(1)\\ = 1000000 + 1 - 2000\\ = 1000001 - 2000\\= 998001[/tex]
999x999:–998,001 right ans
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Answer:
By using identity ( a - b )² = a² + b² - 2ab
Here a = 1000 and b = 1
[tex](999)(999)\\= (999)^{2} \\= ( 1000 - 1 ) ^{2} \\= (1000)^{2} + (1)^{2} - 2(1000)(1)\\ = 1000000 + 1 - 2000\\ = 1000001 - 2000\\= 998001[/tex]
999x999:–998,001 right ans