Explanation:

960 identical packets of soaps each of 10 cm long and 5 cm wide can be kept inside a rectangular box of dimension 80 cm*60 cm*40 cm, what is the height of each packet of soap ?

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★ Solution :-

Given,

» Number of packets of soap = n = 960

» Length of each packet of soap = l = 10 cm

» Breadth of each packet of soap = b = 5 cm

» Length of each packet of soap = L = 80 cm

» Breadth of each packet of soap = B = 60 cm

» Height of each packet of soap = H = 40 cm

• Let the height of the packet of soap be 'h' cm. Then, using the concept, we get,

⟹ l × b × h × n = L × B × H

⟹ 10 × 5 × h × 960 = 80 × 60 × 40

⟹ 50 × 960 × h = 80 × 60 × 40

\: \: \: \: \huge{\longrightarrow \:\:\bold{h \: = \: \dfrac{80 \: \times \: 60 \: \times \: 40}{50 \: \times \: 960}}}⟶h=

50×960

80×60×40

⟹ h = 4 cm

\: \: ➮ \: \: \underline{\boxed{\sf{\red{Hence, \: the \: height \: of \: each \: packet \: of \: soap \: is \: \underline{4 \: cm}}}}}➮

Hence,theheightofeachpacketofsoapis

4cm

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\: \: \boxed{\rm{\purple{Have \: a \: glimpse \: here \: for \: better \: understanding \: }}}

Haveaglimpsehereforbetterunderstanding

• Volume of cuboid = (side)³

• Volume of cylinder = πr²h

where, r is radius and h is height.

• Volume of cone = ⅓(πr²h)

• Total Surface Area of Cuboid = 2(lb + bh + lh)

• Total Surface Area of Cube = 4a²

• Total Surface Area of cylinder = 2πr(r + h)

Height of each packet of soap is 4 cm

hope it helps