What is the equation of a hyperbola with foci at (-2, -2) and (-2, 8), and the length of the conjugate axis is 6? *
0/1
(y-3)^2/16+((〖x+2)〗^2)/9=1
(y-3)^2/16-((〖x+2)〗^2)/9=1
(x-3)^2/16+((〖y+2)〗^2)/9=1
(x-3)^2/16-((〖y+2)〗^2)/9=1
0/1
(y-3)^2/16+((〖x+2)〗^2)/9=1
(y-3)^2/16-((〖x+2)〗^2)/9=1
(x-3)^2/16+((〖y+2)〗^2)/9=1
(x-3)^2/16-((〖y+2)〗^2)/9=1
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Answer:
f x³ - 7x² + 4x - 28 if x-7x² - 2x+1
= (x-2)( f x³+ 5x² - x - 5?
a.x+1
. x+5
2 + 4 − 3) ÷ ( − 1)
4. (
3 +
2 + + 6) ÷ ( + 2)
5. (3
3 + 11= 100000000000000..32132132132132132132132321.3213213213123-321321321321321321.3213
Step-by-step explanation: