9.0L of a gas is found to exert 83.0 kPa at 35.0°C. What would be the required t...

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anne2080 @anne2080

August 2022 1 4 Report

9.0L of a gas is found to exert 83.0 kPa at 35.0°C. What would be the required temperature (in Celsius) to change the pressure to standard pressure?

4.73 L of a gas is collected at 32.0°C and 625.0 mmHg. When the temperature is changed to standard conditions, what is the new pressure?

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Tokamak

PROBLEM:

9.0 L of a gas is found to exert 83.0 kPa at 35.0°C. What would be the required temperature (in Celsius) to change the pressure to standard pressure?

GIVEN:

$\begin{aligned} P_1 & = \text{83.0 kPa} \\ T_1 & = 35.0^{\circ}\text{C} = \text{308.15 K} \\ P_2 & = \text{101.325 kPa} \end{aligned}$

FORMULA:

$T_2 = \dfrac{T_1P_2}{P_1}$

SOLUTION:

$\begin{aligned} T_2 & = \frac{T_1P_2}{P_1} \\ & = \frac{(\text{308.15 K})(\text{101.325 kPa})}{\text{83.0 kPa}} \\ & = \text{376.18 K} \\ & = 376.18 - 273.15 \\ & = \boxed{103.0^{\circ}\text{C}} \end{aligned}$

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PROBLEM:

4.73 L of a gas is collected at 32.0°C and 625.0 mmHg. When the temperature is changed to standard conditions, what is the new pressure?

GIVEN:

$\begin{aligned} P_1 & = \text{625.0 mmHg} \\ T_1 & = 32.0^{\circ}\text{C} = \text{305.15 K} \\ T_2 & = \text{273.15 K} \end{aligned}$

FORMULA:

$P_2 = \dfrac{P_1T_2}{T_1}$

SOLUTION:

$\begin{aligned} P_2 & = \frac{P_1T_2}{T_1} \\ & = \frac{(\text{625.0 mmHg})(\text{273.15 K})}{\text{305.15 K}} \\ & = \boxed{\text{559.5 mmHg}} \end{aligned}$

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