Verified answer

Answer:

The present ages of Father and son are 42 Years and 10 Years respectively.

Step-by-step explanation:

Given :

• Two ears ago = father was five times as old as son
• Two years later = father age will be 8 more than three times the age of his son.

To Find :

• Find their present ages.

Solution :

✯

• Son as x
• Father as 5x

✯

• Son --> x + 2
• Father --> 5x + 2

✯

• Son --> x + (2 + 2)
• Father --> 5x + (2 + 2)

✯

Two years later, father age will be 8 more than three times the age of his son.

★

★ Value of (x + 2)

Son's present age = 10 Years

★ Value of 5x + 2

Father's present age = 42 years

The present ages of Father and son are 42 Years and 10 Years respectively.

Verification :-

As mentioned in the Question, two years later, father's age will be 8 more than three times the age of his son.

✯

• Father = 42
• Son = 10

✯

• Father = 42 + 2 --> 44
• Son = 10 + 2 --> 12

The present ages of Father and son are 42 Years and 10 Years respectively.

Answer:

Two years ago :

Suppose the age of son = X

and the age of father = 5x

The Present ages :

Son present age = X + 2

Father present age = 5x + 2

After two years :

Son age = X + (2 + 2)

Father age = 5x + (2 + 2)

Two years later , his father age will be more than three times the age of her son :

5x + (2 + 2) = 8 + 3 (X + 4)

5x + 4 = 8 + 3x + 12

5x + 4 = 3x + 20

5x - 3x = 20 - 4

2x = 16

X = 8

The age of son's after 2 years = x + 2

The value of X = 8

= 8 + 2

= 10

The age of father after 2 years = 5x + 2

= 5(8) + 2

= 40 + 2

= 42

The age of son's = 10 years .

The age of father = 42 years .