Step-by-step explanation:
Diagram:- Refer the attachment.
Let the height of the first pole be AB = 8m
And height of the season pole be DC = 16m
• AC = 15m
Let us draw a line BE perpendicular to CD. i.e BE ⊥CD
And, AC ⊥ DC
So, BE = AC = 15m
And, AB = EC = 8m
Now:-
By applying Pythagoras Theorem:-
Let, two poles AB and CD
where, AB = 16m and CD = 8m
Now, Draw CE ⊥ AB
So, EB = CD = 8m, EC = BD = 15m
and, ∠AEC = 90°
Here,
→ AB = AE + EB
where,
• Substituting these values •
→ 16 = AE + 8
→ 16 - 8 = AE
→ 8m = AE
→ AE = 8m
Now, In right ∆AEC
↦ H² = P² + B²...........[Pythogoras Theorem]
↦ AC² = AE² + EC²
➠ AC² = AE² + EC²
➠ AC² = 8² + 15²
➠ AC² = 64 + 225
➠ AC² = 289
➠ AC = √(289)
➠ AC = 17m
∴ AC = 17m
Hence, Distance between the tops of the tower is 17m.
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Answers & Comments
Step-by-step explanation:
Diagram:- Refer the attachment.
Given:-
To Find:-
Solution:-
Let the height of the first pole be AB = 8m
And height of the season pole be DC = 16m
• AC = 15m
Let us draw a line BE perpendicular to CD. i.e BE ⊥CD
And, AC ⊥ DC
So, BE = AC = 15m
And, AB = EC = 8m
Now:-
By applying Pythagoras Theorem:-
Given:-
Find:-
Diagram:-
Let, two poles AB and CD
where, AB = 16m and CD = 8m
Now, Draw CE ⊥ AB
So, EB = CD = 8m, EC = BD = 15m
and, ∠AEC = 90°
Solution:-
Here,
→ AB = AE + EB
where,
• Substituting these values •
→ 16 = AE + 8
→ 16 - 8 = AE
→ 8m = AE
→ AE = 8m
Now, In right ∆AEC
↦ H² = P² + B²...........[Pythogoras Theorem]
↦ AC² = AE² + EC²
where,
• Substituting these values •
➠ AC² = AE² + EC²
➠ AC² = 8² + 15²
➠ AC² = 64 + 225
➠ AC² = 289
➠ AC = √(289)
➠ AC = 17m
∴ AC = 17m
Hence, Distance between the tops of the tower is 17m.