Suppose the First Number be a
And, Suppose the Second Number be b
1) Equation
║Now Put the Values of b From the Equation First ║
║Now Put the Value of a in First Equation ║
Therefore,
Answer:
x+2/y+2=1/2
by cross multiply it becomes
2(x+2)=y+2
2x+4=y+2
2x-y+2=0
x-4/y-4=5/11
11(x-4)=5(y-4)
11x-44=5y-20
11x-5y-24=0
22x-11y+22=0
22x-10y-48=0
-y+70=0
-y=-70
y=70
2x-70+2=0
2x-68=0
2x=68
x=68/2
x=34
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Answers & Comments
Given,
To Find,
Solution :
Suppose the First Number be a
And, Suppose the Second Number be b
1) Equation
║Now Put the Values of b From the Equation First ║
║Now Put the Value of a in First Equation ║
Therefore,
Verified answer
Answer:
let first number is x
and second number is y
according to the question
first equation :
x+2/y+2=1/2
by cross multiply it becomes
2(x+2)=y+2
2x+4=y+2
2x-y+2=0
second equation:
x-4/y-4=5/11
by cross multiply it becomes
11(x-4)=5(y-4)
11x-44=5y-20
11x-5y-24=0
now multiply first equation by 11 and second equation by 2
22x-11y+22=0
22x-10y-48=0
by using eliminating method
-y+70=0
-y=-70
y=70
put y=70 in first equation
2x-70+2=0
2x-68=0
2x=68
x=68/2
x=34
that's the answer
hope so it's helpful