Answer:
6p+4q
2m-1/4
hope it helps
I've expanded both of em.
[tex]a) \: (3p+2q) {}^{2} \\ =(3p+2q)(3p+2q)
\\
=(3p)(3p)+(3p)(2q)+(2q)(3p)+(2q)(2q) \\ =9p {}^{2} +6pq+6pq+4q {}^{2}
=9p {}^{2} +12pq+4q {}^{2}
[/tex]
[tex]b) \: (m - \frac{1}{8} ) {}^{2} \\ = (m - \frac{1}{8} )(m - \frac{1}{8} ) \\ =(m)(m)+(m)( - \frac{1}{8} ) + ( - \frac{1}{8} )( m) + ( - \frac{1}{8} ) ( - \frac{1}{8} ) \\ = {m}^{2} + \frac{ - 1}{8} m + \frac{ - 1}{8} m + \frac{1}{64} \\ = {m}^{2} + \frac{ - 1}{4} m + \frac{1}{64} [/tex]
[tex] \mathfrak \color{yellow}\colorbox{cyan} {Please \: mark \: me \: as \: the \: Brainliest.}[/tex]
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Answers & Comments
Answer:
6p+4q
2m-1/4
hope it helps
I've expanded both of em.
Verified answer
[tex]a) \: (3p+2q) {}^{2} \\ =(3p+2q)(3p+2q)
\\
=(3p)(3p)+(3p)(2q)+(2q)(3p)+(2q)(2q) \\ =9p {}^{2} +6pq+6pq+4q {}^{2}
\\
=9p {}^{2} +12pq+4q {}^{2}
[/tex]
[tex]b) \: (m - \frac{1}{8} ) {}^{2} \\ = (m - \frac{1}{8} )(m - \frac{1}{8} ) \\ =(m)(m)+(m)( - \frac{1}{8} ) + ( - \frac{1}{8} )( m) + ( - \frac{1}{8} ) ( - \frac{1}{8} ) \\ = {m}^{2} + \frac{ - 1}{8} m + \frac{ - 1}{8} m + \frac{1}{64} \\ = {m}^{2} + \frac{ - 1}{4} m + \frac{1}{64} [/tex]
[tex] \mathfrak \color{yellow}\colorbox{cyan} {Please \: mark \: me \: as \: the \: Brainliest.}[/tex]