Answer:

Given that

third term A3 = 18 and

sixth term A6 = 486

Let’s assume that the first term is ‘a’ and the common ratio is ‘r’

As we know that An = a*r^(n-1)

so, A3 = a*r^2 ——— Eq1

and A6 = a*r^5 ——— Eq2

Now, Divide Eq2 by Eq1

A6 / A3 = a*r^5 / a*r^2

=> 486 / 18 = r^(5–2)

=> 27 = r^3

=> 3^3 = r^3

=> r = 3

Now put the value of ‘r’ in Eq1

A3 = a*r^2 = 18

=> a*(3)^2 = 18

=> a*9 = 18

=> a*9 / 9 = 18 / 9 (divide both sides by 9)

=> a = 2

Ans: First term ‘a’ = 2 and common ratio ‘r’ = 3

Step-by-step explanation:

Correct me if I'm wrong:)