Hypotenuse=68m
Tanθ=15/8
Perpendicular=15k
Base=8k
Pytho. Theorem
H²=B²+P²
(68)²=(8k)²+(15k)²
4624=64k²+225k²
4624=289k²
4624/289=k²
16=k²
4=k
Perpendicular=15×4=60m
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Verified answer
Hypotenuse=68m
Tanθ=15/8
Perpendicular=15k
Base=8k
Pytho. Theorem
H²=B²+P²
(68)²=(8k)²+(15k)²
4624=64k²+225k²
4624=289k²
4624/289=k²
16=k²
4=k
Perpendicular=15×4=60m