The amount of soil that Jessa added more than Rina.
b. What are given?
⅚ and 1 ⅛
c. What is the operation to be used?
Subtraction
d. What is the number sentence?
1 ⅛ - ⅚ = N
e. What is the answer?
Jessa added 7⁄24 bags of soil more than Rina.
How to Subtract Dissimilar Fractions
The given fractions above are examples of dissimilar fractions. Dissimilar fractions are fractions with different denominators. The problem is asking for the amount of soil that Jessa added more than Rina. The clue words in the given word problem above is "how much more". This means that we have to subtract their bags of soil.
These are the steps in subtracting dissimilar fraction.
Find their LCD or least common denominator.
Make the fractions similar by dividing the LCD by the denominator, times the numerator.
Answers & Comments
Answer:
a. What is asked?
The amount of soil that Jessa added more than Rina.
b. What are given?
⅚ and 1 ⅛
c. What is the operation to be used?
Subtraction
d. What is the number sentence?
1 ⅛ - ⅚ = N
e. What is the answer?
Jessa added 7⁄24 bags of soil more than Rina.
How to Subtract Dissimilar Fractions
The given fractions above are examples of dissimilar fractions. Dissimilar fractions are fractions with different denominators. The problem is asking for the amount of soil that Jessa added more than Rina. The clue words in the given word problem above is "how much more". This means that we have to subtract their bags of soil.
These are the steps in subtracting dissimilar fraction.
Find their LCD or least common denominator.
Make the fractions similar by dividing the LCD by the denominator, times the numerator.
Subtract the numerators and copy the denominator.
Simplify, if possible.
Solution:
Step by step explanation:
Step 1: LCD
1 ⅛ = 8, 16, 24
⅚ = 6, 12, 18, 24
Step 2: LCD ÷ denominator × numerator
1 ⅛: 24 ÷ 8 × 1 = 3 -> 1 3⁄24
⅚: 24 ÷ 6 × 5 = 20 -> 20⁄24
Step 3: Subtract
1 3⁄24 - 20⁄24 = 27⁄24 - 20⁄24 = 7⁄24
Jessa added 7⁄24 bags of soil more than Rina.
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