7. Construct an angle of measure 45° using compass and ruler.
8. Subtract -8y from -3y.
9. Draw any triangle XYZ and mark the points:
a. A, B in the interior of Δ XYZ.
b. C, D in the exterior of Δ XYZ.
10. Convert the following into linear equation:
a. Three times a number y decreased by 1 is 4.
b. 15 less than a number a is 7.
11. A man buys a radio set for ₹900 and sells it for ₹972. What is his profit or loss
percent?
12. Identify any two pairs of perpendicular line segments in each of the following
need diagram also
8. Subtract -8y from -3y.
9. Draw any triangle XYZ and mark the points:
a. A, B in the interior of Δ XYZ.
b. C, D in the exterior of Δ XYZ.
10. Convert the following into linear equation:
a. Three times a number y decreased by 1 is 4.
b. 15 less than a number a is 7.
11. A man buys a radio set for ₹900 and sells it for ₹972. What is his profit or loss
percent?
12. Identify any two pairs of perpendicular line segments in each of the following
need diagram also
Answers & Comments
Answer:
8) -8y and -3y
= (-8 -3) y
= (8+3) y
= -11y
10)
A = 3a × 1y - 1/4
B = 15 < a/7
Verified answer
7 ) Steps:
Construct a perpendicular line
Place compass on intersection point
Adjust compass width to reach start point
Draw an arc that intersects perpendicular line
Place ruler on start point and where arc intersects perpendicular line
Draw 45 Degree Line
( see attached image )
8) -11y ( -8y-3y = 8y + 3y = 11 y ) here , 8 y is greater so sign in 11 y will be of - so your final answer is -11y
10 ) a ) 3y-1 = 4
b) 15-a = 7
11 ) C.P = Rs.900
S.P = Rs.972
Now,
Profit = S.P - C.P
= Rs.972 - Rs.900
= Rs.72
Again,
Profit Percent = Profit/C.P × 100%
= 72/900 × 100%
= 8%
Hence, His profit percent is 8%.
12 ) A ) CD TO BE
AND
BC TO ED
B) BA TO DC