In this problem, we are asked to find the quadratic equation having the two zeros, 23 and -5.
First solution is we multiply the factors:
x = 23; (x - 23)
x = -5; (x + 5)
f(x) = (x - 23)(x + 5)
f(x) = - 18x -115 (Final Answer)
Second solution is analyzing that quadratic equation is f(x) = a + bx + c with numerical coefficients a, b, and c. The product of the roots is equal to c/a and the sum of the roots is -b/a. Calculating:
Answers & Comments
Answer:
f(x) =
- 18x -115
Step-by-step explanation:
In this problem, we are asked to find the quadratic equation having the two zeros, 23 and -5.
First solution is we multiply the factors:
x = 23; (x - 23)
x = -5; (x + 5)
f(x) = (x - 23)(x + 5)
f(x) =
- 18x -115 (Final Answer)
Second solution is analyzing that quadratic equation is f(x) = a
+ bx + c with numerical coefficients a, b, and c. The product of the roots is equal to c/a and the sum of the roots is -b/a. Calculating:
c/a = product = 23(-5) = -115
-b/a = sum = -(23 - 5) = -18
To find the quadratic equation:
f(x) = a
+ bx + c
f(x) =
+ (-
)x +![\frac{c}{a} \frac{c}{a}](https://tex.z-dn.net/?f=%5Cfrac%7Bc%7D%7Ba%7D)
f(x) =
-18x - 115 (Final Answer)