The specific resistance of conductor is 5.5 * 10 ^ - 6 Ωm .
Explanation:
As per the question
We have given ,
L = 4 m
R = 7/ 4 Q
diameter = 4 mm
r = 0.002 mm
We have to find
specific resistance of conductor
Specific Resistance (”ρ”) is a property of any conductive material, a figure used to determine the end-to-end resistance of a conductor given length and area in this formula: R = ρl/A.
Specific resistance is defined as "the resistance offered per unit length and unit cross-section area of that material when a known quantity of voltage applied at its end ''. The SI unit of specific resistance is Ohm-m.
ρ= (R x a)/ l
specific resistance = 7 /4 * pi * 0.002 * 0.002 /11 * 4* 1000 * 1000
Answers & Comments
Answer:
[tex]5.5 \times {10}^{ - 6} Ωm[/tex]
Explanation:
Please find the explanation in the attached photograph.
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Answer:
The specific resistance of conductor is 5.5 * 10 ^ - 6 Ωm .
Explanation:
As per the question
We have given ,
L = 4 m
R = 7/ 4 Q
diameter = 4 mm
r = 0.002 mm
We have to find
specific resistance of conductor
Specific Resistance (”ρ”) is a property of any conductive material, a figure used to determine the end-to-end resistance of a conductor given length and area in this formula: R = ρl/A.
Specific resistance is defined as "the resistance offered per unit length and unit cross-section area of that material when a known quantity of voltage applied at its end ''. The SI unit of specific resistance is Ohm-m.
ρ= (R x a)/ l
specific resistance = 7 /4 * pi * 0.002 * 0.002 /11 * 4* 1000 * 1000
specific resistance = 4 * 22 * 2 * 2 / 4* 1000* 1000*4 *7 /2
specific resistance = 5.5 * 10 ^ - 6 Ωm
Therefore , The specific resistance of conductor is 5.5 * 10 ^ - 6 Ωm .
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