Learning Task 3 : Solve the problem. Provide an illustration if necessary. ( 3 points each)
1.The length of o a rectangle is 12 cm and its width is 2 cm less than ¾ of its length. Find the
area of a rectangle .
2.A circular clock with a circumference of 88 cm, is mounted on the wall. How much area of
the wall did it occupy ( Use : π = 22/7 ).
3. The length of a rectangle is 52 cm and its perimeter is 200 cm . What is the area of the rectangle?
1.The length of o a rectangle is 12 cm and its width is 2 cm less than ¾ of its length. Find the
area of a rectangle .
2.A circular clock with a circumference of 88 cm, is mounted on the wall. How much area of
the wall did it occupy ( Use : π = 22/7 ).
3. The length of a rectangle is 52 cm and its perimeter is 200 cm . What is the area of the rectangle?
Answers & Comments
Answer:
1.)To find the area of the rectangle, we need to first find its width. We are given that the length is 12 cm. Let's use the formula for the width in terms of the length:
Width = (3/4) x length - 2
Width = (3/4) x 12 - 2
Width = 7 cm
Now we can use the formula for the area of a rectangle:
Area = length x width
Area = 12 cm x 7 cm
Area = 84 cm²
Therefore, the area of the rectangle is 84 cm².
2.)The circumference of the clock is given as 88 cm, which means that the diameter is 88/π cm ≈ 28 cm. The area of a circle is given by the formula:
Area = π x (radius)²
Radius = diameter/2 = 28/2 = 14 cm
Area = π x 14²
Area ≈ 615.75 cm²
Therefore, the area of the wall that the clock occupies is approximately 615.75 cm².
3.)We are given the length and perimeter of the rectangle. Let's use the formula for the perimeter of a rectangle:
Perimeter = 2 x (length + width)
200 cm = 2 x (52 cm + width)
200 cm = 104 cm + 2 x width
2 x width = 200 cm - 104 cm
2 x width = 96 cm
width = 48 cm
Now we can use the formula for the area of a rectangle:
Area = length x width
Area = 52 cm x 48 cm
Area = 2496 cm²
Therefore, the area of the rectangle is 2496 cm².
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