Answer:

[tex](2c + 1) \times (3c + 1)[/tex]

Step-by-step explanation:

[tex]6 {c}^{2} + 5c + 1[/tex]

[tex]write \: 5c \: as \: a \: sum \\ \\ 6 {c}^{2} \red{ + 3c + 2c \: } \: { + 1} \\ \\ factor \: out \: 3c \: from \: the \\ expression\\ \\ \red {3c \times(2c + 1) } { + 2c + 1}\\ \\ factor \: out \: 2c + 1 \: from \\ the \: expression \\ \\ \red{(2c + 1) +(3c + 1)}[/tex]