6)A potential difference of 2 V is applied across a resistance 1 ohm. Hence the number of electrons flowing through

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February 2023 1 1 Report

6)A potential difference of 2 V is applied across a resistance 1 ohm. Hence the number of electrons flowing through it in one second is A. 1.25 * 10¹9 B. 2 * 10¹⁹ C. 1.6* 10 29 D. 3.2 * 10¹⁹

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ndmlnandini

Answer:n=1.25x10^19

Explanation:By ohms law

V=IR

2=Ix1

I=2ampere

Charge flowing through it in 1sec

Q=it

Q=2x1

q=2C

the number of electrons flowing in 1sec

n=q/e (e=1.6x10^-19)

n=2/ 1.6x10^-19

n=1.25x 10^19

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