Answer:

My Answer is 324

Step-by-step explanation:

Tell me if it is correct or not

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• Above question is based on exponents and powers. Let understand the question, in the question we have asked to find the value of [ (6²) × (–3)²]² ÷ [(4²×3²) × (1¹+0¹+2¹)²]. So, Let's start solving the problem

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[tex] \sf { \bold {[ (6²) × (–3)²]² ÷ [(4²×3²) × (1¹+0¹+2¹)²] }}[/tex]

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[tex] \sf \bold{= (36×9)² ÷ [(16×9)×(1+0+2)²]}[/tex]

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[tex] \sf \bold{=(36² × 9²) ÷ [(16×9) × (3)²]}[/tex]

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[tex] \sf \bold{= 36×36×9×9 ÷ 16×9×9}[/tex]

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[tex] \sf \bold{ = \frac{36 \times 36 \times \cancel{ 9 }\times \cancel{ 9}}{16 \times \cancel{ 9} \times \cancel{ 9}} }[/tex]

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[tex] \sf \bold{= \frac{ \cancel4 \times 9 \times \cancel 4 \times 9}{ \cancel4 \times \cancel 4} }[/tex]

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[tex] \sf{ \bold \red {= 81}}[/tex]