Step-by-step explanation:
Given , Base of ∆ = 24.8 cm
Height of ∆ = 16.5 cm
one of the diagonal = 22 cm
Let the other diagonal be x cm
Area of triangle = Area of rhombus
{ 1 /2 x B X H } = { product of diagonal / 2 }
1 / 2 X 24.8 cm X 16.5 cm = 22 x X / 2
12.4 cm x 16.5 cm = 22x / 2
22x = 204.6 x 2
x = 204.6 x 2 / 22
x = 409.2 / 22
x = 18.6 cm
hence , the other diagonal be = 18.6cm
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Answer: hope you mark brainliest
Step-by-step explanation:
Given , Base of ∆ = 24.8 cm
Height of ∆ = 16.5 cm
one of the diagonal = 22 cm
Let the other diagonal be x cm
Area of triangle = Area of rhombus
{ 1 /2 x B X H } = { product of diagonal / 2 }
1 / 2 X 24.8 cm X 16.5 cm = 22 x X / 2
12.4 cm x 16.5 cm = 22x / 2
22x = 204.6 x 2
x = 204.6 x 2 / 22
x = 409.2 / 22
x = 18.6 cm
hence , the other diagonal be = 18.6cm