Answer:
x= -a and x= 0.5a
Step-by-step explanation:
2x²+ ax - a² = 0
the standard quadratic equation is in form of
ax²+bx=c
and formula to find its roots is
x = (-b±√(b²-4ac))/(2a)
so putting values of our equation in the formula
x = (-a±√(a²+8a²))/4
x = (-a±√(9a²))/4
x = (-a±3a)/4
x = -a
and
x = 0.5a
priyu theirs a sign mistake in ans which u ans me now only
p value is +2
12-14 is -2 u write +2 correct ur silly mistakes for board dear.
thanks for effort
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Verified answer
Answer:
x= -a and x= 0.5a
Step-by-step explanation:
2x²+ ax - a² = 0
the standard quadratic equation is in form of
ax²+bx=c
and formula to find its roots is
x = (-b±√(b²-4ac))/(2a)
so putting values of our equation in the formula
x = (-a±√(a²+8a²))/4
x = (-a±√(9a²))/4
x = (-a±3a)/4
x = -a
and
x = 0.5a
Answer:
priyu theirs a sign mistake in ans which u ans me now only
p value is +2
12-14 is -2 u write +2 correct ur silly mistakes for board dear.
thanks for effort