Let x be the first odd integer, then the next two odd consecutive integers are x+2 and x+4.
Equation: x + (x+4) = 5(x+2) - 87
Solution: x = 25, third integer = 29.
Step-by-step explanation:
According to the problem statement:
The first and third of three odd consecutive integers are added: x + (x+4) = 2x + 4
The result is 87 less than five times the second integer: 5(x+2) - 87 = 5x - 73
Now we can set up an equation by equating the expressions we just found:
2x + 4 = 5x - 73
Solving for x:
2x + 77 = 5x
77 = 3x
x = 25.67
Since x must be an odd integer, we can conclude that x = 25. Thus the three odd consecutive integers are 25, 27, and 29, and the third integer is 29.
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Answers & Comments
Let x be the first odd integer, then the next two odd consecutive integers are x+2 and x+4.
Equation: x + (x+4) = 5(x+2) - 87
Solution: x = 25, third integer = 29.
Step-by-step explanation:
Let x be the first odd integer, then the next two odd consecutive integers are x+2 and x+4.
According to the problem statement:
The first and third of three odd consecutive integers are added: x + (x+4) = 2x + 4
The result is 87 less than five times the second integer: 5(x+2) - 87 = 5x - 73
Now we can set up an equation by equating the expressions we just found:
2x + 4 = 5x - 73
Solving for x:
2x + 4 = 5x - 73
2x + 77 = 5x
77 = 3x
x = 25.67
Since x must be an odd integer, we can conclude that x = 25. Thus the three odd consecutive integers are 25, 27, and 29, and the third integer is 29.