Verified answer

Step-by-step explanation:

Let, the poly. be p(x)=2x2−7x+5.

Then, p(x)=0⇒2x2−7x+5=0.

∴2x2−5x−−−−−−−−−2x+5−−−−−−=0.

∴x(2x−5)−1(2x−5)=0.

∴(2x−5)(x−1)=0.

∴ The zeroes of p(x) are 52,and,1.

We select, α=52andβ=1.

Letting α0=2α+1,andβ0=2β+3, we have,

α0=2(52)+1=6,andβ0=2(1

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