Answer: ∴R=[tex]\frac{20}{3}[/tex]% or [tex]6\frac{2}{3}[/tex]%
Step-by-step explanation:
[tex]\frac{3}{5} (P+\frac{P*R*15}{100})=\frac{P*R*15}{100}[/tex]
⇒[tex]\frac{3P}{5}=\frac{15PR}{100}-\frac{9PR}{100}[/tex]
⇒[tex]\frac{3P}{5}=\frac{9PR}{100}[/tex]
⇒[tex]\frac{3}{5}=\frac{9R}{100}[/tex]
⇒R=[tex]\frac{100}{15}[/tex]
∴R=[tex]\frac{20}{3}[/tex]% or [tex]6\frac{2}{3}[/tex]%
Answer:
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Verified answer
Answer: ∴R=[tex]\frac{20}{3}[/tex]% or [tex]6\frac{2}{3}[/tex]%
Step-by-step explanation:
[tex]\frac{3}{5} (P+\frac{P*R*15}{100})=\frac{P*R*15}{100}[/tex]
⇒[tex]\frac{3P}{5}=\frac{15PR}{100}-\frac{9PR}{100}[/tex]
⇒[tex]\frac{3P}{5}=\frac{9PR}{100}[/tex]
⇒[tex]\frac{3}{5}=\frac{9R}{100}[/tex]
⇒R=[tex]\frac{100}{15}[/tex]
∴R=[tex]\frac{20}{3}[/tex]% or [tex]6\frac{2}{3}[/tex]%
Answer:
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Step-by-step explanation:
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