[tex] \large \orange { \underbrace{ \bf{ \red{ \: \: \: \: \: \: \: \: \: \: \: \: Question \: \: \: \: \: \: \: \: \: \: \: \: }}}}[/tex]
What is the area of a piece of rectangular card bound of measure 3/7m by 2/5m.
______________________________________
No Spam
NEED RIGHT ANSWER WITH EXPLANATION
______________________________________
Answers & Comments
[tex] \sf \: Solution[/tex]
Given that ;
Length of a piece of rectangular card = 3/7 m
Breadth of a rectangular piece = 2/5 m.
Area of rectangle = L × B
Area of rectangle = 3/7 × 2/5 = 3×2/7×5
Area of rectangle = 6/35 m²
Verified answer
Question :-
What is the area of a piece of rectangular cardboard of measure [tex]\tt \frac{3}{7} m[/tex] by [tex]\tt \frac{2}{5} m[/tex] ?
Answer :-
[tex] \tt\[ \dfrac{6}{35} \: m^{2} \][/tex]
Solution :-
[tex] \text{Length of piece of cardboard \( \tt=\dfrac{3}{7} \: m \)}[/tex]
[tex] \text{ Breadth of piece of cardboard \( \tt =\dfrac{2}{5} \: m \)}[/tex]
[tex] \text{ Area of rectangle \( = \) length \( \times \) breadth}[/tex]
So, area of piece of rectangular cardboard
[tex]\rm=\left\lgroup\frac{3}{7} \times \frac{2}{5}\right\rgroup m^{2}\quad \boxed{ \tt\color{red} =\frac{6}{35} \: m^{2}} \\ [/tex]