observe picture in that solution there
Answer: -26 -15√3
Step-by-step explanation:
Question -> [tex]\frac{5 - 3\sqrt{3}}{5+3\sqrt{3}}[/tex]
Rationalising the denominator.
[tex]\frac{(5 - 3\sqrt{3})^{2} }{(5^{2}) - (3\sqrt{3})^{2}}\\[/tex]
[tex]\frac{((5)^2+(3\sqrt{3})^2-2X5X-(3\sqrt{3}) }{25-9X3}[/tex]
[tex]\frac{25+27-30\sqrt{3} }{-2}\\[/tex]
[tex]\frac{52-30\sqrt{3} }{-2}[/tex]
[tex]\frac{2(26-15\sqrt{3})}{-2}[/tex]
[tex]\frac{1(26-15\sqrt{3})}{-1}[/tex]
[tex]\frac{-1(26-15\sqrt{3})}{1}[/tex]
[tex]\frac{-26+15\sqrt{3})}{1}\\[/tex]
15√3 - 26
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observe picture in that solution there
Verified answer
Answer: -26 -15√3
Step-by-step explanation:
Question -> [tex]\frac{5 - 3\sqrt{3}}{5+3\sqrt{3}}[/tex]
Rationalising the denominator.
[tex]\frac{5 - 3\sqrt{3}}{5+3\sqrt{3}}[/tex] × [tex]\frac{5 - 3\sqrt{3}}{5 - 3\sqrt{3}}[/tex]
[tex]\frac{(5 - 3\sqrt{3})^{2} }{(5^{2}) - (3\sqrt{3})^{2}}\\[/tex]
[tex]\frac{((5)^2+(3\sqrt{3})^2-2X5X-(3\sqrt{3}) }{25-9X3}[/tex]
[tex]\frac{25+27-30\sqrt{3} }{-2}\\[/tex]
[tex]\frac{52-30\sqrt{3} }{-2}[/tex]
[tex]\frac{2(26-15\sqrt{3})}{-2}[/tex]
[tex]\frac{1(26-15\sqrt{3})}{-1}[/tex]
[tex]\frac{-1(26-15\sqrt{3})}{1}[/tex]
[tex]\frac{-26+15\sqrt{3})}{1}\\[/tex]
15√3 - 26
If this answer was helpful to you then please mark me as THE BRAINLIEST (*^_^*)