50gm ice at 20°C is mixed with 60gm water at 60°c and 10gm steam at 200°c find final temp of mixture
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Answer:
55°C
Explanation:
Given : 50gm of ice (M1) it's temperature 20°C (T1)
60gm water (M2) it's temperature 60°c (T2)
10gm steam (M3) it's temperature 200°c (T3)
Temperature of the mixture :
= (M1×T1) + (M2×T2) + (M3×T3) ÷ M1 + M2 + M3
= (50 × 20) + (60 × 60) + (10 × 200) ÷ 50 + 60 + 10
= 1,000 + 3600 + 2000 ÷ 120
= 6,600 ÷ 120
= 55°C