5. You sight a rock climber on a cliff at a 32° angle of K. 1,179.18 ft. elevation. The horizontal ground distance to the cliff is 1000 ft. Find the line sight distance to the rock climber?
To find the line sight distance to the rock climber, we can use trigonometry. Given that the elevation is 1,179.18 ft and the horizontal ground distance is 1,000 ft, we can use the tangent function to determine the line sight distance.
The tangent of an angle is defined as the ratio of the opposite side to the adjacent side. In this case, the opposite side is the elevation (1,179.18 ft) and the adjacent side is the horizontal ground distance (1,000 ft).
Let's calculate the line sight distance (d) using the tangent function:
tan(θ) = opposite/adjacent
tan(32°) = 1,179.18 ft / 1,000 ft
Now, we can solve for the line sight distance (d):
d = tan(32°) * 1,000 ft
d ≈ 1.635 * 1,000 ft
d ≈ 1,635 ft
Therefore, the line sight distance to the rock climber is approximately 1,635 ft.
Answers & Comments
Answer:
To find the line sight distance to the rock climber, we can use trigonometry. Given that the elevation is 1,179.18 ft and the horizontal ground distance is 1,000 ft, we can use the tangent function to determine the line sight distance.
The tangent of an angle is defined as the ratio of the opposite side to the adjacent side. In this case, the opposite side is the elevation (1,179.18 ft) and the adjacent side is the horizontal ground distance (1,000 ft).
Let's calculate the line sight distance (d) using the tangent function:
tan(θ) = opposite/adjacent
tan(32°) = 1,179.18 ft / 1,000 ft
Now, we can solve for the line sight distance (d):
d = tan(32°) * 1,000 ft
d ≈ 1.635 * 1,000 ft
d ≈ 1,635 ft
Therefore, the line sight distance to the rock climber is approximately 1,635 ft.