If r be the radius and h be the height, then volume = πr²h
If radius is doubled and height remain same,
the volume will be = π(2r)²2h=
=4πr²h= 4× Volume
The volume is four times more than the original volume.
Let the height be h and radius be r.
Therefore, curved surface area = 2πrh
Now, the radius is doubled. So, the new radius
r′ =2r
New curved surface area =2πr′h
=2π×2r×h
=2×2πrh
=2(Curved surface area of old cylinder)
solved .....
Answer:
the volume becomes 4 times of its
and the curve surface area becomes double of its.
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Verified answer
If r be the radius and h be the height, then volume = πr²h
If radius is doubled and height remain same,
the volume will be = π(2r)²2h=
=4πr²h= 4× Volume
The volume is four times more than the original volume.
Let the height be h and radius be r.
Therefore, curved surface area = 2πrh
Now, the radius is doubled. So, the new radius
r′ =2r
New curved surface area =2πr′h
=2π×2r×h
=2×2πrh
=2(Curved surface area of old cylinder)
solved .....
Answer:
the volume becomes 4 times of its
and the curve surface area becomes double of its.