Answer:
Given 4y + 3/2 * 2 2/5
= 4y + 3/2 = 2/5
= 5(4y + 3) = 2(2)
= 20y + 15 = 4
=20y= 4-15
=20y= 11
= y =11/20
therefore, y=11/20 , or 0.7333
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Answer:
Given 4y + 3/2 * 2 2/5
= 4y + 3/2 = 2/5
= 5(4y + 3) = 2(2)
= 20y + 15 = 4
=20y= 4-15
=20y= 11
= y =11/20
therefore, y=11/20 , or 0.7333