Answer:
As you may have noticed, there is a pattern in the given series.
The first term has the numerator as 1 and denominator as 2.
The second term has the numerator as 2 and denominator as 3.
The third term has the numerator as 3 and denominator as 4 and so on.
Thus, you can see that the ith term can be given by i/(i+1).
Since the Fifth term of the sequence is required, on substituting i=5 , you will get 5/6, which should be the required answer.
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Answers & Comments
Answer:
As you may have noticed, there is a pattern in the given series.
The first term has the numerator as 1 and denominator as 2.
The second term has the numerator as 2 and denominator as 3.
The third term has the numerator as 3 and denominator as 4 and so on.
Thus, you can see that the ith term can be given by i/(i+1).
Since the Fifth term of the sequence is required, on substituting i=5 , you will get 5/6, which should be the required answer.
Answer:
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