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Answer:

Question

Rahul can do 2/7 of a certain work in 6 days while Suresh can do 3/5 of the same work in 9 days. They started work together but after 7 days Tahul left the work. Find in how many days Suresh can complete the remaining work?

Solution

Rahul, 2/7 = 6

whole work in 21

Suresh, 3/5 = 9

whole work in 15

work together = 1/15+1/21 = 12/105

together 7 days = 7*12/105 = 12/15

work done by 4/5

remaining work 1-4/5 = 1/5

Suresh done 1/5 work in 1/5*15 = 3days

Mathematics