Verified answer

Let's call the length of the rectangle "L" and the width "W"

We know that the width of the rectangle is 3/5 of its length, so we can set up the following equation:

W = (3/5)L

We also know that the perimeter of a rectangle is equal to twice the sum of its length and width. So we can set up the equation:

2(L + W) = 640

Now we can substitute the first equation into the second equation:

2(L + (3/5)L) = 640

Solving for L, we get:

2L + 6L/5 = 640

Combining like terms, we get:

20L/5 = 640

Dividing both sides by 20/5, we get:

L = 160

Now we can use the first equation to find the width:

W = (3/5)L

W = (3/5)(160)

W = 96

So the dimensions of the rectangle are:

Length: 160 meters

Width: 96 meters