5. Mely opened a savings account at a nearby bank. Her initial deposit was P10,000. For three consecutive months, she deposited 51,200 per week as her savings. On the fourth month, she withdrew P11,200. How much was her account balance?
pls don't answer nonsense or if you don't know answer or report and pls show solution if you show solution the rate 5 and brainliest
pls don't answer nonsense or if you don't know answer or report and pls show solution if you show solution the rate 5 and brainliest
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Answer:
Step-by-step explanation:
51 200 per week for 3 months. 4 weeks in a month = 4 x 51 200 = 204 800
204 800 x 3 = 614400 (because there are 3 months)
614400 - 11 200 = 603 200 (we minus the 11200 because she withdrew, meaning took some money from the account)
The initial deposit, (A minimum deposit or initial deposit is the minimum amount of money required to open an account with a financial institution, such as a bank or brokerage firm) was 10k pesos, so then
603 200 + 10k = 613 200
There's your answer, 613 200 pesos.
statement:
Therefore, there was 613 200 pesos in her bank account balance.
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Answer:
₱13,200
Step-by-step explanation:
Given: P10,000 initial deposit
P1,200 deposited per week for 3 consec. months
P11,200 withdrawals
Required: Account Balance
Therefore: P1200 × 12 (4 weeks in 1month and the given is 3month, 3(4)) = P14,400
P14,400 + P10,000 = P24,400
P24,400 - P11,200 = P13,200