Step-by-step explanation:

Solutions :-

5)

Given that

Length of the one diagonal of a rhombus = 6 cm

Length of the other diagonal = Thrice of the length of the one diagonal

=> 3×6

=> 18 cm

We have

d1 = 6 cm

d2 = 18 cm

We know that

Area of a rhombus whose diagonals d1 and d2 is

(d1 d2)/2 sq.units

=> Area of the given rhombus

=> (6×18)/2 sq.cm

=> 108/2 sq.cm

=> 54 sq.cm

Area of the given rhombus = 54 sq.cm

Option D

6)

Given that

The height of the Parallelogram = 5 cm

Length of the base of the Parallelogram

= two times it's height

= 2×5 cm

= 10 cm

we have

b = 10 cm

h = 5 cm

We know that

Area of a Parallelogram whose base b units and height h units is bh sq.units

=> Area of the paralellogram

=> 10×5 sq.cm

=> 50 sq.cm

Area of the Parallelogram is 50 sq.cm

Option C

7)

Given that

Let the base of the Parallelogram be b cm

Height of the Parallelogram = 8 cm

Area of a Parallelogram whose base b units and height h units is bh sq.units

=> b×8 sq.cm

=> 8b sq.cm

According to the given problem

Area of the parallelogram 64 sq. cm.

=> 8b = 64

=> b = 64/8

=> b = 8 cm

Base of the Parallelogram = 8 cm

Option A

Used formulae:-

• Area of a rhombus whose diagonals d1 and d2 is (d1 d2)/2 sq.units

• Area of a Parallelogram whose base b units and height h units is bh sq.units

Verified answer

Answer:

5. In a Rhombus, length of the one diagonal is 6 cm, another diagonal is thrice the other.

Then its area is

(A) 14 cm

(B) 28 cm

(C) 22 cm

(D) 54cm

6. In a parallelogram the base is two times its height if the height is 5cm,then the area is

(A) 25sq.cm

(B) 10 sq.cm

(C) 50sq.cm

(D) 54sq. cm

7. Area of the parallelogram 64 sq. cm. If its hieght is 8 cm then base is

(A) 8cm

(B)

512cm

(C) 256cm

(D) 16cm