5. If the square of y varies inversely as the square root x and y = 0.6 when x = 49, what is the value of

December 2022 1 0 Report

5. If the square of y varies inversely as the square root x and y = 0.6 when x = 49, what is the value of y when x = 4?

Step-by-step explanation:

Given:

y = 0.6 ==> y² = (0.6)² = 0.36

x = 49 ==> √x = √49 = 7

y² = k/√x

0.36 = k / 7

[0.36 = k / 7] 7

2.52 = k

y² = k / √x

y² = 2.52 / √4

y² = 2.52 / 2

y² = 1.26

y = √1.26

y = 1.12249721603

not that sure