Answer:
A)
x = 34°
y = 77°
B)
x=47°
y=99°
Step-by-step explanation:
In Triangle SPQ,
LPSQ = x (Opp. Angles of Equal Sides)
112° + 2x = 180° (Angle Sum Property)
2x = 180°-112° = 68°
x = 68°/2 = 34°
In Triangle QSR,
LRSQ = 180°-(57°+80°) {Angle Sum Property}
LRSQ = 180° - 137 ° = 43°
y = x + LRSQ = 43°+34° = 77°
B) In Triangle RWQ,
LWRQ = 26° (Vertically Opposite Angles)
Note that PQRS is a Parallelogram.
73 ° = x + 26° (Opposite Angles of a Parallelogram)
x = 73°-26° = 47°
LQRT = 180°-LR = 180°- 73° = 107° (Linear Pair)
LQRT = 107° = LWRQ + LRWQ (Exterior Angle Theorem)
107°-26° = LRWQ = 81°
y + LRWQ = 180° (Linear Pair)
y = 180°-81° = 99°
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Verified answer
Answer:
A)
x = 34°
y = 77°
B)
x=47°
y=99°
Step-by-step explanation:
A)
In Triangle SPQ,
LPSQ = x (Opp. Angles of Equal Sides)
112° + 2x = 180° (Angle Sum Property)
2x = 180°-112° = 68°
x = 68°/2 = 34°
In Triangle QSR,
LRSQ = 180°-(57°+80°) {Angle Sum Property}
LRSQ = 180° - 137 ° = 43°
y = x + LRSQ = 43°+34° = 77°
B) In Triangle RWQ,
LWRQ = 26° (Vertically Opposite Angles)
Note that PQRS is a Parallelogram.
73 ° = x + 26° (Opposite Angles of a Parallelogram)
x = 73°-26° = 47°
LQRT = 180°-LR = 180°- 73° = 107° (Linear Pair)
LQRT = 107° = LWRQ + LRWQ (Exterior Angle Theorem)
107°-26° = LRWQ = 81°
y + LRWQ = 180° (Linear Pair)
y = 180°-81° = 99°
Hope it helps. Pls mark as brainliest
Answer:
These are answers of 2 figures
pls pls mark me as brainliest and pls follow me.....!!!!!!!