Answer:
[tex]let \: the \: consecutive \: numbers \: be \: x, \: x + 1 \: and \: x + 2. \\ if \: they \: are \: divided \: by \: 10, \: 17 \: and \: 26 \: respectively. \\ then \\ \frac{x}{10} + \frac{x + 1}{17} + \frac{x + 2}{26} = 10 \\ 442x + 260(x + 1) + 170(x + 2) = 442 \times 100 \\ 872x + 600 = 442 \times 100 \\ x = 50 \\ so \: the \: consecutive \: numbes \: are \: 51, \: 52 \: and \: 53.[/tex]
50, 51, and 52 are the three consecutive numbers
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Answer:
[tex]let \: the \: consecutive \: numbers \: be \: x, \: x + 1 \: and \: x + 2. \\ if \: they \: are \: divided \: by \: 10, \: 17 \: and \: 26 \: respectively. \\ then \\ \frac{x}{10} + \frac{x + 1}{17} + \frac{x + 2}{26} = 10 \\ 442x + 260(x + 1) + 170(x + 2) = 442 \times 100 \\ 872x + 600 = 442 \times 100 \\ x = 50 \\ so \: the \: consecutive \: numbes \: are \: 51, \: 52 \: and \: 53.[/tex]
Answer:
50, 51, and 52 are the three consecutive numbers